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    <script>
        // 4. 封装一个方法 返回阶乘和  求1!+2!+3!+....+n!]
        function jc(n) {
            var res = 1;
            for (var i = 1; i <= n; i++) {
                res = res * i;
            }
            return res;
        }
        
        function jch(n1){
            var num = 1;
            for (var i = 1; i <= n1; i++){
                num = num + jc(i);
            }
            return num;
        }
        console.log(jc(5));
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